Trong mặt phẳng tọa độ $Oxy$, cho $\vec{u}=-2\vec{i}+\vec{j}$. Tìm tọa độ của vectơ $\vec{u}$.

(AI giải đề cho tôi)
Vectơ $\breve{0}000vecu=-2\vec{i}+\vec{j}$ c\u0000\u0000 t\u0000\u0000a \u0000\u0000\u0000 l\u0000\u0000 h\u0000\u0000 s\u0000\u0000 c\u0000\u0000a $\vec{i}$ v\u0000\u0000 $\vec{j}$: $\vec{u}=(-2;1)$. Kh\u0000\u0000p v\u0000\u0000i \u0000\u0000\u0000p \u0000\u0000n A, c\u0000\u0000ng kh\u0000\u0000p b\u0000\u0000ng \u0000\u0000\u0000p \u0000\u0000n m\u0000\u0000 \u0000\u0000\u0000 146, c\u0000u 23 (A).