Chọn đáp án B
E $\stackrel{\text{chảy}}{\to }$ $\{\begin{array}{l}{n}_{{\text{CO}}_2}=a\\ n_{{\text{H}}_2\text{O}}=b\\ n_{{\text{N}}_2}=c\end{array}$ $\to$ $\{\begin{array}{l}44a-18b=66,14\\ \stackrel{\text{NAP.332}}{\to }3a-3c=2.3,105\\ \stackrel{\text{NAP.332}}{\to }a-b=c-n_E\to n_E=b+c-a=b-2,07\end{array}$

Dồn chất $\to$ m = 14a + 58c + 18(b - 2,07)
$\stackrel{\text{BTKL}}{\to }$ 0,5m = 33,75 - 18n${}_{\text{E}}$
$\to$ 0,5(14a + 58c + 18b - 37,26) = 33,75 - 18.(b - 2,07)
$\to$ $\{\begin{array}{l}a=2,44\\ b=2,29\to n_E=0,22\to \overline{C}=11,1\\ c=0,37\end{array}$
$\stackrel{\text{Venh}}{\to }$ $\{\begin{array}{l}\text{GlyAlaVal}:0,18\\ {\text{Y}}_5:0,04\end{array}$

Xếp hình $\to$ $\Delta n_C$ = 0,08 $\to$ GlyAla${}_3$Val $\to$ 1 : 3