Bài Tập Trắc Nghiệm Chuyên Đề: Mặt cầu (Toán học Lớp 12)

$I(1;-2;-1),R=4$.

$I(1;-2;-1),R=2$.

$I(-1;2;1),R=2$.

$I(-1;2;1),R=4$.

$(x+1{)}^2+y^2+(z-2{)}^2=3$.

$(x+1{)}^2+(y-2{)}^2+(z+3{)}^2=9$.

$(x-1{)}^2+(y+2{)}^2+(z-3{)}^2=9$.

$(x-1{)}^2+(y+2{)}^2+(z-3{)}^2=3$.

$(x-2{)}^2+y^2+(z-1{)}^2=4$.

$(x+2{)}^2+y^2+(z+1{)}^2=2$.

$(x+2{)}^2+y^2+(z+1{)}^2=4$.

$(x-2{)}^2+y^2+(z-1{)}^2=2$.

$r=\frac{1}{2}$.

$r=\sqrt{3}$.

$r=\frac{\sqrt{3}}{2}$.

$r=\frac{\sqrt{2}}{2}$.

$7\pi$.

$14\pi$.

$\sqrt{7}\pi$.

$2\sqrt{7}\pi$.

$(x-1{)}^2+y^2+z^2=\sqrt{14}$.

$x^2+y^2+z^2=56$.

$x^2+y^2+z^2=2\sqrt{14}$.

$x^2+y^2+z^2=14$.

64

8

4

$x^2+(y-3{)}^2+(z-2{)}^2=3$.

$x^2+(y-3{)}^2+(z-2{)}^2=12$.

$(x+1{)}^2+(y-4{)}^2+(z-1{)}^2=12$.

$(x-1{)}^2+(y-2{)}^2+(z-3{)}^2=12$.

$39$.

$3$.

$13$.

$\frac{28}{13}$.

$(x+1{)}^2+(y-2{)}^2+(z+3{)}^2=6$.

$(x-1{)}^2+(y+2{)}^2+(z-3{)}^2=24$.

$(x+1{)}^2+(y-2{)}^2+(z+3{)}^2=24$.

$(x-1{)}^2+(y+2{)}^2+(z-3{)}^2=6$.

$(x-3{)}^2+(y+1{)}^2+(z-6{)}^2=36$.

$(x-1{)}^2+(y+4{)}^2+(z-1{)}^2=18$.

$(x-6{)}^2+(y+2{)}^2+(z-12{)}^2=36$.

$(x-3{)}^2+(y+1{)}^2+(z-6{)}^2=18$.

$(x-3{)}^2+(y+1{)}^2+(z-4{)}^2=4$.

$(x-3{)}^2+(y+1{)}^2+(z-4{)}^2=2$.

$(x-3{)}^2+(y-1{)}^2+(z-4{)}^2=4$.

$(x-3{)}^2+(y-1{)}^2+(z-4{)}^2=16$.

$1$.

$\sqrt{7}$.

$2\sqrt{2}$.

$7$.

( x + 1) + ( y - 2 ) + ( z - 1) = 3

( x + 1) + ( y - 2 ) + ( z + 1) = 9 .
2 2 2 2 2 2

( x + 1) + ( y - 2 ) + ( z + 1) = 3

( x + 1) + ( y - 2 ) + ( z - 1) = 9 .
2 2 2 2 2 2

1 1

$\int$ f ( x ) dx = 2 I = $\int$ []3 f ( x ) - 1[] dx

$2$.

$4$.

$2\sqrt{2}$.

$\sqrt{2}$.